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10 hours ago, Monke King said:

Idk

First exponents x^2 multiply by 3 3x^2 then add 4x then add 4= 3x^2+4x+4

to differetiate 3(x^2) + 4x + 6 we start with 3x^2 and multiply the by the exponent and then decrease the exponent by 1 so 6x^1 which is 6x for the 4x we do the same so 4x^1 becomes 4x^0 x^0=1 so 4*1=4 then we do the 4, 4 is 4x^0 multiplying by 0 makes it 0 so it disapears making for a total of 6x+4

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1 hour ago, life king said:

to differetiate 3(x^2) + 4x + 6 we start with 3x^2 and multiply the by the exponent and then decrease the exponent by 1 so 6x^1 which is 6x for the 4x we do the same so 4x^1 becomes 4x^0 x^0=1 so 4*1=4 then we do the 4, 4 is 4x^0 multiplying by 0 makes it 0 so it disapears making for a total of 6x+4

I don’t understand but tbh I’m just learning  algebra 1 so.. 🤷

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